Can I find the direction of $2$ $n$-dimensional vectors (only $2$ vectors), clockwise or anticlockwise.
For example, If I have $2$ vectors $a=(1,1,1,1,1)$, $b=(2,3,5,6,7)$, function angle(a, b) returns $30°$, and angle $ (b, a) $ will return $-30$°.
I know that the direction can be defined in 2 dimensional space by $x_1y_2 - x_2y_1$.
Can I map the $2$ n-dimensional vectors to $2$ $2$-dimensional vectors(keeping the angle between $2$ vectors not changed or the position not changed between each other) and then check the direction by $2$-dimensional ways? OR any way to find the plane defined by the $2$ $n$-dimensional vectors(From my view, even if they are defined in n-dimensional space, but only $2$ vectors, if the $2$ vectors represent for $2$ intersected lines in n-dimensional space, can I find a $2$-dimensional space(plane) containing the $2$ lines so that I can check the angle and direction in $2$-dimensional ways, like $x_1y_2 - x_2y_1$)?
From my understanding, we can know the direction, clockwise or not in $2$-dimensional space is that we can got the vectors related position by some ways, like using sin/cos and also the formula mentioned, these ways check all the conditions in four quadrant.
But in n-dimensional space, it's hard to compare. Can I map the $2$ $n$-dimension vectors to $2$-dimensional vectors without information losing since in most cases, dimensional reduction will lose information(in this case, if $2$ $n$-dimensional vectors stand for $2$ lines, they can completely present by $2$ $2$-dimensional lines)? Or can I compare the raw n-dimensional vectors directly to check the related position between each other, such as if $a[0] == b[0]$ (or maybe the projection is the same), then we can get the direction information, if not, compare another dimension between the vectors
Above discussion may be not right. Please correct me or any other right ways to do this.
Appreciate for your help