The Witten conjecture on the intersection numbers of stable classes on the moduli space of curves was proved by Kontsevich by considering the graphs embedded on genus $g$ surfaces with $n$ marked points. However, this is far too complex to even attempt to explain here, but here is something in a similar vein:
Problem: Let $P$ and $Q$ be polynomials over $\mathbb C$. What is the smallest possible degree of the polynomial $P^3 - Q^2$, in terms of degrees of $P$ and $Q$?
Answer: for monic $P$ and $Q$ with $P^3\neq Q^2$ and $\deg P = 2m$ and $\deg Q = 3m$ we have $\deg(P^3-Q^2)\geq m + 1$, with the equality attained for infinitely many $m$.
This is the Davenport-Stothers-Zannier bound, conjectured by Davenport in 1965, the inequality proven by Davenport in 1965, the sharpness by Stothers in 1981, and generalised by Zannier in 1995.
This problem can be reformulated in terms of plane graphs:
Reformulation: is there, for every $m$, a plane graph such that it has $3m$ edges, $2m$ vertices of degree 3, and such that all but one face are of degree 1?
Answer: yes, proof: For inductive basis, take $m=1$. Draw the tree with 2 vertices and 1 edge, and add a loop to every vertex (a loop is counted twice for the purposes of degree). Inductive step: delete a single loop from a vertex $v$ and add two leafs to $v$. Now add a loop to each new vertex.
Why does this prove the bound? Plane graphs with $V$ vertices, $E$ edges and $F$ faces are in a 1-1 correspondence with holomorphic maps $f\colon\mathbb C\to\mathbb C$ over $\overline{\mathbb Q}$ of degree $E$ such that $f^{-1}(0)$ has $V$ elements, $f^{-1}(1)$ has $E$ elements, and $f^{-1}(\infty)$ has $F-1$ elements (plus one element at infinity), with ramification indices of points in the preimages $f^{-1}(0)$ and $f^{-1}(\infty)$ corresponding to the degrees of vertices and faces (this correspondence is up to orientation preserving homeomorphisms on the graph side, and composing with a Möbius transformation on the holomorphic side), i.e. maps $f=g/h$ such that $g$ and $h$ are polynomials where the roots of $g$ correspond to the vertices of $G$, the roots of $g-h$ to the edges of $G$, and the roots of $h$ to the faces of $G$.
This is a special case of the so-called Grothendieck-Belyi correspondence, and the fundamental result in the Theory of Dessins d'Enfants, which states that the pairs $(X,f)$, where $X$ is a compact Riemann surface defined over the algebraic numbers, and $f\colon X\to\hat{\mathbb{C}}$ is a holomorphic map to the Riemann sphere $\hat{\mathbb{C}}$, ramified over $\{0,1,\infty\}$, are in a 1-1 correspondence with graphs cellularly embedded on compact surfaces. This correspondence gives a dictionary between problems about algebraic curves and problems about embedded graphs.
Now suppose $P^3(x)-Q^2(x)=R(x)$. If $f(x)=\frac{P^3(x)}{R(x)}$, then $f(x)-1=\frac{Q^2(x)}{R(x)}$. If $P$ has degree $2m$ and no multiple roots, then the zeros of $P^3$ correspond to $2m$ vertices of degree 3. If $Q$ has degree $3m$ and no multiple roots, then the zeros of $Q^2$ corresponds to $3m$ edges. By the Euler-Poincare formula, a plane graph with $2m$ vertices and $3m$ edges has $m+2$ faces. Therefore, $R$ must have $m+1$ distinct zeros, since once face is attained for $x=\infty$ (here $\infty$ is understood as "the north pole" on the Riemann sphere).
The 1981 paper of Stothers which first completed the proof of Davenport's conjecture has approx. 20 pages. But, as you can see, when the dictionary between holomorphic maps and plane graphs is established (which at present time is fairly well known, and covered by several books through an elementary approach), the proof is reduced to half a page.
Reference: Lando, Zvonkin - Graphs on Surfaces and their Applications, with appendix by D. Zagier, section 2.5.