One way of phrasing the intermediate value theorem is as follows:
(1) Let $f:[-1,1] \to \Bbb{R}$ be continuous. Suppose that $f(-1)=-1$ and $f(1)=1$. Then there there is some $a \in [-1, 1]$ with $f(a)=0$.
By regarding $[-1, 1]$ as the "unit ball" in $\Bbb{R}$, and the set $\{-1, 1\}$ as its boundary the "unit sphere", you can write down an analogous statement for $\Bbb{R}^2 \cong \Bbb{C}$:
(2) Let $f: D \to \Bbb{C}$ be continuous, where $D$ is the closed unit disc in $\Bbb{C}$. Suppose that $f(z)=z$ whenever $|z|=1$. Then there is some $a \in D$ with $f(a)=0$.
This is also a true statement. Like the intermediate value theorem, it's physically very intuitive if you think about it in the right way. One physical version of (2) might be:
(2') If there's a laser pointer shining down the middle of a pipe, and the end of the pipe is covered by an opaque balloon, there's no way of stretching the balloon to reveal the laser pointer (without taking it off the pipe or tearing it).
It is, however, somewhat harder to prove than the intermediate value theorem. It's equivalent to the two-dimensional version of the Brouwer fixed-point theorem, a famous theorem in algebraic/combinatorial topology (in fact, all the proofs of the Brouwer fixed-point theorem that I know of use something like (2) as a key lemma).