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In Rudin's Principles of Mathematical Analysis 1.1, he first shows that there is no rational number $p$ with $p^2=2$. Then he creates two sets: $A$ is the set of all positive rationals $p$ such that $p^2<2$, and $B$ consists of all positive rationals $p$ such that $p^2>2$. He shows that $A$ contains no largest number and $B$ contains no smallest.

And then in 1.2, Rudin remarks that what he has done above is to show that the rational number system has certain gaps. His remarks confused me.

My questions are:

  1. If he had shown that no rational number $p$ with $p^2=2$, this already gave the conclusion that rational number system has "gaps" or "holes". Why did he need to set up the second argument about the two sets $A$ and $B$?

  2. How does the second argument that "$A$ contains no largest number and $B$ contains no smallest" showed gaps in rational number system? My intuition does not work here. Or it is nothing to do with intuition?

Larry
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    FWIW, this {A, B} partition is called a Dedekind cut – PM 2Ring Apr 30 '20 at 01:10
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  • It's subtly but there is not reason to think that rationals not have a number $q$ so that $q^2=2$ is a "hole"? After all there is no rational number $q$ where $q$ has sharp teeth and eats rabbits, is a hole. And there is not rational number $q$ where $q^2=-1$ is a hole. $x^2=2$ could simply be... something that doesn't exist. ....
  • – fleablood Apr 30 '20 at 01:48
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    But the hole comes in noting we can get close to it. We can hone in and find infinitely many $p_i$ and $q_i$ where $q_i-p_i$ can get as small as we like but $p_i^2 < 2 < q_i^2$. So the road between $p_i$ to $q_i$ ought to be "smooth" (they can be as close as we like) but the have a "jump" somehow we jump fro $p_i^2 < 2$ to $q_i^2> 2$ without passing a $r^2 = 2$ in between. – fleablood Apr 30 '20 at 01:48
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    This answer may be helpful https://math.stackexchange.com/a/95366/6455. There are physical and intuitive explanations for the use of the words "hole" and or "gap". – Rex Butler Apr 30 '20 at 15:39
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    By a "gap" he says that although rationals are arbitrarily close to $\sqrt{2}$ both smaller and larger than it, no rational is equal to $\sqrt{2}$ . So the mere fact that $\sqrt{2}$ is irrational does not in itself illustrate the assertion that the rational number system has "gaps". For example, $-1$ is never the square of a real number. But this fact alone does not say that the real number system has "gaps". It does not, the reals form a complete ordered field. – student May 05 '20 at 18:29