The number of onto functions from $A \rightarrow B$ when $a \ge b$ is:
$\sum_{j=0}^{b}$$(-1^{j})$ ${b}\choose{j}$$(b-j)^{a}$
I cannot find a derivation for this. Can someone please help?
The number of onto functions from $A \rightarrow B$ when $a \ge b$ is:
$\sum_{j=0}^{b}$$(-1^{j})$ ${b}\choose{j}$$(b-j)^{a}$
I cannot find a derivation for this. Can someone please help?