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I know that the formula of probability is the following:

P= FO(favorable outcomes)/PO(possible outcomes)

What I do not understand is what is the number of PO(possible outcomes) ?

If we take into consideration the order of the dice (i,e 2,1 is a different outcome than 1,2)then there are 36 possible scenarios.

But when we are not interested in the order (in Backgammon game the order is not relevant) there will be only 21 possible scenarios.

In this particular scenario which should be the probability ? 6/36=1/6 or 6/21=2/7 ?

dj_frunza
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    The outcomes must themselves have equal probability. Do the 21 outcomes in Backgammon have equal probabilities? – Ben W Apr 01 '20 at 10:08

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Order is relevant. Think of the two dice as different colours. Then Blue = 1 red = 2 is different from blue = 2 red = 1. You can list all possible outcomes in a 6 by 6 grid.

Ray
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