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I have been inspired by this question: Expectation of the sum of two random variables whose probabilities are individualy bounded I am wondering if solution can be generalized for $$ E(A+B)^p, $$ where $p>1$.

volond
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1 Answers1

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You can apply almost exactly the same procedure by just using that $$ \mathbb{P}(|A+B|^p>x) \; = \; \mathbb{P}(|A+B|>x^{1/p})$$ since the $p$-th root is increasing on $[0,\infty)$.