Hence that $K$ is principal ideal domain. Prove that every ring $R$ is isomorphic with $K$ is principal ideal domain.
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1Prove that ideals generated by single elements are mapped to ideals generated by single elements in an isomorphism. – Rushabh Mehta Mar 31 '20 at 14:50
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Give $I$ is a ideal of $R$. We must prove that $I$ is principal ideal.
By $R$ is isomorphic with $K$ that exist $f: R \rightarrow K$ is isomorphic.
When $f(I) \in K$ and $K$ is P.I.D then exist $a\in K$ that $f(I) = (a) = aK$.
By $f$ is isomorphic then exist reverse mapping $f^{-1}: K \rightarrow R$ is isomorphic. Thus, $I = f^{-1}\left[f(I) \right] = f^{-1}(aK) = f^{-1}(a)f^{-1}(K)=f^{-1}(a)R$
Infer I is principal domain.
So $R$ is P.I.D

Tung Nguyen
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1@PhucLe i think this post prove very clearly. https://math.stackexchange.com/questions/78110/is-f-1fa-a-always-true – Tung Nguyen Mar 31 '20 at 15:04