Find all $[x] \in \mathbb{Z}/30\mathbb{Z}$ such that $[x]^2 = [x] $
I am really not sure how to start on this problem, please help me!
Find all $[x] \in \mathbb{Z}/30\mathbb{Z}$ such that $[x]^2 = [x] $
I am really not sure how to start on this problem, please help me!
Hint: $x^2 \equiv x\pmod{30}\iff x^2\equiv x\pmod{p}$ for $p=2,3,5$, and the latter only has $[0]_p$ and $[1]_p$ as solutions.