Let $(\Omega, F, P)$ be a probability space. Suppose $X(\omega)=C$, $\forall\omega \in \Omega$ where $C$ is a constant.
How do I show that $X$ is independent of any other random variable?
Let $(\Omega, F, P)$ be a probability space. Suppose $X(\omega)=C$, $\forall\omega \in \Omega$ where $C$ is a constant.
How do I show that $X$ is independent of any other random variable?
Hint: $X^{-1}(A)=\emptyset$ or $X^{-1}(A)=\Omega$ for any Borel set $A$. Now apply the definition.
From measure theory point of view, two Random Variables are independent iff for all measurable sets in their sigma algebra they are independent (i.e. standard definition with pushing product outside the probability)
As Kavi gave you a hint: try to think what is the result of applying preimage of $\cal{X}$ for different events (from sigma algebra). Well, either it includes that constant $C$ or it does not. Therefore, it is either empty (probability is 0) or everything (probability is 1). So on your RHS (the one with product of probabilities) you have either 0 or you forget about $\cal{X}$ random variable (as multiplying by 1 does not change anything). Now, let's inspect LHS (probability of two events happening at the same time) and you quickly notice that it is either 0 or probability of the second event and the cases are disjoint.