Here's some background to the answer. A group is an order pair of a set and a binary operation ⋅ from that set to itself satisfying the following properties.
- ⋅ is associative
- There is an identity element
- Every element has an inverse with respect to that operation.
One element is said to be an inverse of the other when their product in both orders is the identity element. The order of a group is its cardinality. Also, 2 integers are said to be congruent modulo a certain integer when their difference is a multiple of that integer. For example, 2 is congruent to 6 modulo 4. This is written $2 \equiv 6 \mod 4$. The remainder of 10 on division by 4 is 2 so we can also write $10 \mod 4 = 2$. Some people would write $6 = 10 \mod 4$ to mean $6 \equiv 10 \mod 4$ but this is technically incorrect because it is saying that 6 is equal to $10 \mod 4$. But $10 \mod 4 = 2$ and $6 \neq 2$ so $6 \neq 10 \mod 4$.
2 has the property that not all powers of it have a cyclic multiplication modulo group. No other prime number has that property. Take any positive integer. Now take the powers of one more than it modulo the cube of the starting integer such as powers of 11 modulo 1,000. Taking powers of 11 modulo 1,000, we get 001, 011, 121, 331, 641, 051, 561, 171, 881, 691, 601. In any base x, after the $x^{th}$ power, the first digit is a 1 when the base is odd and is 1 more than half the base when the base is even. This shows that the numbers 1 more than a multiple of x modulo $x^3$ form a cyclic group when ever x mod 4 is 1, 3, or 4 but not when x mod 4 is 2. This is something special about the property of being an even number. Another property such as the property of being a multiple of 3 doesn't have something special about it like that.
The multiplication modulo group of any product of 2 odd primes is never cyclic. That's because you can always find a number that's 1 more than a multiple of one of those primes and 1 less than a multiple of the other one of those primes. It's square must be 1 more than a multiple of the semiprime. For example, $21^2$ is 1 more than a multiple of 55. It turns out that all this comes from the fact that 2 is the only prime number that's so small that any integer that's not a multiple of it is 1 more than a multiple of it, making the multiplication modulo group of any odd prime have order an even number.
A subgroup of a group is a subset that is a group with the operation of the original group. A coset of the group is one where each member can be gotten by right multiplying any member of the coset by a member of the original subgroup. When the product of any member of one coset by any member of another coset always gets you a member of the same coset, the subgroup is said to be a normal subgroup. We can then form the cosets into a group and call it the quotient group. When ever a subgroup has 2 cosets, it is necessarily a normal subgroup. For any other prime number, it is not always the case that a subgroup with that number of cosets is a normal subgroup.