How to find this expression $(1000!\mod 3^{300})$?
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Using this, the highest power of $3$ in $1000!>300$
So, the remainder $=0$

lab bhattacharjee
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4It's even easier than that: Of the factors in $1000!$, there are 333 multiples of 3. And since $333>300$, … – Harald Hanche-Olsen Apr 06 '13 at 14:53
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$3$ goes into $1000!$ at least $300$ times, since it divides $3, 6, 9, \dots, 900$, and hence $3^{300} \mid 1000!$.

Clive Newstead
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Hint $\rm\ B^\color{#C00}A \mid (AB)!\, =\, 1\cdot\cdot\: B\,\cdot\cdot\: 2B\,\cdot\cdot\ 3B\,\cdots \color{#C00}AB$
thus $\:3^{300}\mid 900!\mid 1000!$

Math Gems
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