Is there any manipulation for the equation $x^{x^x}=c$ to be presented in a tractable Lambert-W-function form? I'm certain that $x^x=c$ is possible.
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Indeed $x^x=c$ is solved by $$x=\frac{\ln(c)}{W(\ln(c))}$$ I don't think there is any such expression for $x^{x^x}=c$ though – Maximilian Janisch Jan 29 '20 at 10:00
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1Does this answer your question? Can $x^{x^x}=k$ be solved using the W function? – cineel Jan 11 '22 at 03:30