5

As the question says. Are there non-trivial groups isomorphic to their automorphisms group?

(By the way i am İbrahim İpek but i lost the password of my account and also mail :/ Is there anything anyone can do?)

3 Answers3

6

And for an example where $Z(G)\neq \{e\}$, so that the automorphism group is not just the inner automorphism group, take the Dihedral group of order $8$.

Arturo Magidin
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4

If $G$ is a complete group, that is, with trivial center and no outer automorphisms, then $$G\simeq \text{Aut}(G)$$ as every automorphism is the conjugation by some element, and the map $g\mapsto g\cdot g^{-1}$ has a trivial kernel.

3

Yes, for example we have $\text{Aut}(S_n) \cong S_n$ if $n \neq 2,6$.

Con
  • 9,000