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I am supposed to determine the converge field of:

$$\sum_{n=1}^{\propto }n^{2}x^{n-1}$$ I do not know how to solve it, because I cannot see the path how to use ration criterion, or Cauchy–Hadamard criterion.

I know that the correct asnwer is $\left ( -1,1 \right )$

Can anyone help me?

1 Answers1

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Use the fact that radius of convergence = 1/r Where r = Lim $a_n^{1/n}$

Here that limit is clearly 1. Hence it converges in (-1,1) surely. Now check -1,1 points explicitly.