Does there exist an example of four convex sets lying in $\mathbb{R}^2$ such that the intersection of every 3 of them contains a unit-length interval but the intersection of all 4 of them does not?
Asked
Active
Viewed 112 times
1 Answers
3
Yes. Consider the four rectangles
(0 , 0), (1 , 0), (1 ,1.5), (0 ,1.5)
(0.5, 0), (1.5, 0), (1.5,1.5), (0.5,1.5)
(0 , 0), (0 , 1), (1.5, 1), (1.5, 0)
(0 ,0.5), (0 ,1.5), (1.5,1.5), (1.5,0.5)
Then the intersection of each triple is a $1 \times 0.5$ (or $0.5 \times 1$) rectangle, and the intersection of all four is a $0.5 \times 0.5$ square.

Guus B
- 648