While trigonometric ratios such as $\sin{(90°+\theta)}$, $\cos{(180°-\theta)}$, and so on are shown to work for acute angle values of $\theta$ in textbooks, they hold for all values of $\theta$. Even certain proofs make use of the fact. For instance, the proof my textbook demonstrates for $\sin{(270°+\theta)}$ is like: $$\sin{(270°+\theta)}=\sin{\{180°+(90°+\theta)\}}=-\sin{(90°+\theta)}=-\cos{\theta}$$ Evidently $(90°+\theta)>90°$, and this proof is assuming that $\sin{(180°+\theta)}$ holds for all values of $\theta$. The same goes for $\sin{(A+B)}$. While it is initially stated to be true for $A+B<90°$, it works for all values of $A+B$. I guess that makes sense if the previous one does.
Now, isn't there like, a general proof or a logical argument showing why this is happening? Or why trigonometric ratios work for all values of $\theta$? Any help is appreciated.