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What is the remainder when $7^{113}$ is divided by $50$? is there any method to approach such question

1 Answers1

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We know that $7^2=49 \equiv -1 \pmod{50}$, so we can write, that:

$$7^{113}=7 \times (7^2)^{56} \equiv 7 \times (-1)^{56} \equiv 7 \pmod{50}$$

Henno Brandsma
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Andronicus
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