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If $f:X \to Y$ is a function and $U$ and $V$ are subsets of $X$, then $f(U\cap V) \subseteq f(U) \cap f(V) $.

I know that if this statement dealt with equality it would be false, but what about this? I have a feeling it is true since $\emptyset$ would be a subset of any set. Any proofs/guidance would be appreciated.

Asaf Karagila
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1 Answers1

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Hint:

$A\subseteq B\implies f(A)\subseteq f(B)$.

Bernard
  • 175,478