Seems intuitive. Like the fact that $\sqrt 3 \not \in \mathbf{Q}(\sqrt 2)$. But how to approach actually proving it? The proof of this fact doesn't seem to generalize well.
Asked
Active
Viewed 115 times
1
-
4Duplicate of The square roots of different primes are linearly independent over the field of rationals (the general proof there works here and more generally) – Bill Dubuque Apr 05 '19 at 22:03