$$i^2 = i \cdot i = (\sqrt{-1}) \cdot (\sqrt{-1}) = ({\sqrt{-1}})^2 = -1 \tag{1}$$ $$i^2 = i \cdot i = \underbrace{\sqrt{-1}\cdot\sqrt{-1} = \sqrt{(-1)\cdot(-1)}}_{?} = \sqrt{(-1)^2} = 1 \tag{2}$$
What are the conceptual or logical errors here?
TIA
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Every nonzero complex number has two square roots. – Angina Seng Mar 03 '19 at 08:45
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@LordSharktheUnknown: It's also true for real number... – user649261 Mar 03 '19 at 08:46