My question is if the Lie algebra of $GL_{+}(n,\mathbb C)$ = {$A \in \mathbb C^{n \times n} |\det(A) > 0$} is the same as of $GL(n,\mathbb C)$. Futhermore I have a problems understanding what is the underlying manifold of these two Lie groups (are they also the same?).
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5What does it mean for a complex number to be greater than $0$? – Randall Feb 25 '19 at 16:46
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For complex numbers, $GL_n(\Bbb C)$ is already connected, so there is only one connected component.
What's an easy way to show that $GL(n,\mathbb C)$ is connected?

Dietrich Burde
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