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Evaluate the sum of the infinite series $1+\cos x + \cos^2 x + \cos ^3 x ...$ for $0<x<\pi$

So am I correct in thinking that $$1+\cos x + \cos^2 x + \cos ^3 x ...=\sum ^\infty _{n=0} \cos^n x$$ which is just a geometric series with common ratio $\cos x$ and first term 1. So the sum of the series should be $$\sum ^\infty _{n=0} \cos^n x =\frac{1}{1-\cos x}$$ However, the answer to the question is $\frac1 2 \csc^2(\frac x 2)$. Is my method not correct or do I need to apply some identities, if so how do I get it into this form? any help would be great.

H.Linkhorn
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2 Answers2

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What you did is fine. And then you use the fact that\begin{align}1-\cos(x)&=1-\left(\cos^2\left(\frac x2\right)-\sin^2\left(\frac x2\right)\right)\\&=2\sin^2\left(\frac x2\right).\end{align}

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Please note how $1-cos(x) = \frac{1}{2} sin^2(\frac{x}{2})$ and $\frac{1}{1-cos(x)} = \frac{1}{2sin^2(\frac{x}{2})}=\frac{csc^2(\frac{x}{2})}{2}$.

PackSciences
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