Construct a group that has exactly 5 elements of order 4.
I wonder if it is possible. I tried $U(8)$ but it has $\{[1], [3], [5],[7]\}$ as elements which has order $4$ but it has only $4$ elements. So I am quite stuck.
Construct a group that has exactly 5 elements of order 4.
I wonder if it is possible. I tried $U(8)$ but it has $\{[1], [3], [5],[7]\}$ as elements which has order $4$ but it has only $4$ elements. So I am quite stuck.
An element has the same order as its inverse.
The inverse operation pairs off elements, except for those which are their own inverse.
Elements which are their own inverse have order 1 or 2.
Conclusion: elements of order 4 (or any other order greater than 2) come in pairs. It's not possible to have exactly 5.