I have the function $f(x,y)=e^{\alpha x^2+y^2}-1$. I want to find for which values is convex or not in its domain. If i find where $g(x,y)={\alpha x^2+y^2}$ is convex so the function f is convex?
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I don't understand – user495707 Jan 15 '19 at 18:30
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Almost an answer https://math.stackexchange.com/questions/108393/is-the-composition-of-n-convex-functions-itself-a-convex-function – mathcounterexamples.net Jan 15 '19 at 18:34
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Look at the Hessian. – copper.hat Jan 15 '19 at 18:35
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The hessian of f? – user495707 Jan 15 '19 at 19:07
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Yes. Or $g$. ${}{}{}$ – copper.hat Jan 15 '19 at 19:18
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$e^{g(x,y)}$ is convex if $g$ is convex? – user495707 Jan 15 '19 at 19:34