Prove that a point in a circle equidistant from any three points on the circle is the centre
$\frac{1-1}{1-1}=?$
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lioness99a
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For the second part: $0/0$ is not defined in mathematics. – Matti P. Jan 11 '19 at 13:50
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why both terms do not get cancelled? – Mohammad Noor Alam Jan 11 '19 at 13:52
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why answer is not 1 – Mohammad Noor Alam Jan 11 '19 at 13:52
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1https://math.stackexchange.com/questions/26445/division-by-0 – EdOverflow Jan 11 '19 at 13:59
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2@MohammadNoorAlam if $\frac 00=n$, then $0 \cdot n = 0$. How many ways can this be solved? – Rhys Hughes Jan 11 '19 at 14:02
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if a/a=1, then why not (1-1)(1-1)=1? – Mohammad Noor Alam Jan 13 '19 at 08:22
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Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.
Levent
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