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We learned expression of deduce, i.e. =>.

But now I dont have capable reason for I agree I represent True if assumption is False.

Anybady there having to explain reason for its deduce?

Best regards,

2 Answers2

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Here is a table that should help

\begin{array}{|c|c|c|} \hline P & Q & P\Rightarrow Q \\ \hline T & T & T \\ \hline T & F & F \\ \hline F & T & T \\ \hline F & F & T \\ \hline \end{array}

For the first row, $P$ and $Q$ are both assumed true thus $P \Rightarrow Q$ will be true. For the second row, $P$ is true and $Q$ is false thus $P\Rightarrow Q$ will say okay well what is the result of the ending statement? false since $Q$ is the result of the ending statement in $P\Rightarrow Q$. Same logic in reverse applied to the third row. Latly, $P$ and $Q$ are now both false, thus $P\Rightarrow Q$ will return true since both statements both have the same assumed false value. I hope that is clear.

As an extension to this exercise try this one to solidify your understanding:

\begin{array}{|c|c|c|} \hline P & Q & Q\Rightarrow P \\ \hline T & T & \\ \hline T & F & \\ \hline F & T & \\ \hline F & F & \\ \hline \end{array}

Wolfy
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One rather intuitive understanding is that the equivalence $\Leftrightarrow$ can be understood as a conjunction of $\Leftarrow$ and $\Rightarrow$ thus $F\Rightarrow X$ has to be true independent of whether $X$ stands for true or false. As long as the implication does not get violated by a clear example that falsifies it ($T\Rightarrow F$) it is considered to be true.

  • But if you have given intuitve function pretend F is T and T is F, can you distinguish between F and T. I don't understand. – quickybrown Nov 24 '18 at 21:17