$$\frac{0.314^5}{120}=2.5437065e\!−\!5$$
I did this calculation by my android phone's calculator.
I can't understand the result I got (The RHS of calculation).
Please help. What is this?
$$\frac{0.314^5}{120}=2.5437065e\!−\!5$$
I did this calculation by my android phone's calculator.
I can't understand the result I got (The RHS of calculation).
Please help. What is this?
phone calculators often use this input for large or small numbers. In this context: $$'e-5'=10^{-5}$$ so your answer is: $$2.5437065\times10^{-5}$$
$2.5437065e−5$ is really $2.543706 \times 10^{−5} = 0.00002543706$.
(I haven't checked the arithmetic.)
It seems that this is your first encounter with the so-called scientific notation.
For very large or very small numbers, you need many digits but only the first significant ones are useful. Hence you shift the decimal point after the first digit and compensate by multiplying by a suitable power of ten.
E.g.
$$2573475675632465243747463476727\approx2.57347\times10^{30}$$
$$0.000000000000052352344643\approx 5.23523\times 10^{-14}.$$
$e\,n$ or $E\,n$ is used as an abbreviation of $\times10^{n}$ (for exponent). This is legacy from the first scientific programming languages.
E
is shorter than x10^
. If I am right, usage of lowercase e
was later popularized by the C language.
–
Oct 21 '18 at 13:57