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Let $f:[a, b] \to \Bbb R$ be increasing and $g:f[a, b] \to \Bbb R$ be integrable. Is $g\circ f$ integrable on $[a, b]$?

It seems integrable to me since $g$ is integrable on $[f(a),f(b)]$ since for any partition $P'$ of $[a,b]$, we can choose partition $P''$ of $[f(a),f(b)]$ such that $$U(g\circ f,P')−L(g\circ f,P')≤U(g,P'')−L(g,P'')$$ Is this reasoning correct?

Hash Nuke
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$$f:[0,1]\to[0,1] ,\quad f(x) = x^2 $$ $$ g: [0,1] \to \mathbb R ,\quad g = \begin{cases} \frac{1}{\sqrt x} & x\neq 0\\ 0 & x=0 \end{cases} $$

Notice that $f$ is increasing, $g$ is integrable, while $g\circ f$ is not integrable.

Calvin Khor
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    $g$ is not bounded and according my definition of my book, Riemann integrability only applied to bounded function. This is from Abbott Understanding Analysis page 227 – Hash Nuke Oct 13 '18 at 15:01
  • @HashNuke fair, but it seems UserS has edited your question to add measure-theory as a tag. If you don't agree with him, you should undo his edit. – Calvin Khor Oct 13 '18 at 15:02