a cyclist travels 30 km in one hour
1) Demonstrate that there is an interval of 10 minutes such that the cyclist has traveled 5 Km
2) Is there always a time interval of 40 minutes during which he will have traveled 20 Km?
for the first question, that's what I did : Note f the function that represents the distance traveled by the cyclist as a function of time (expressed in minutes). $f$ is a continuous function, $f (0) = 0$ and $f (60) = 30$. We want to prove that there is a time interval of 10 minutes such that the cyclist has traveled 5 km. In other words, we want to find $x \in [0,50]$ such that $f (x + 10) -f (x) = 5$.
Suppose that such an $x$ does not exist. By the intermediate value theorem, we know that: or else,
$\forall x∈ [0,50]$, we have $f(x + 10) -f (x)> 5$.
or, $\forall x∈ [0,50]$, we have $f (x + 10) -f (x) <5$.
In the first case, we have $f (60) = f (60) -f (50) + f (50) -f (40) + f (40) -f (30) + f (30) -f (20) + f (20 ) -f (10) + f (10)-f(0) > 6 × 5=30$. which is a contradiction. In the second case, we would find $f (60) <30$, which is also a contradiction. The hypothesis formulated is therefore false: there exists $x∈ [0,50]$ such that $f (x + 10) -f (x) = 5$.
For the second question,I Think that the answer in No but i don't know how to prove it .
Do you have any suggestions ?