find the lim of the sequance when n $\to \infty $
$\sqrt{2} ,\sqrt{2\sqrt{2}} , \sqrt{2\sqrt{2\sqrt{2}}} ,.....$
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1Hint: Take logarithms. – hmakholm left over Monica Sep 24 '18 at 04:14
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Let $x=\sqrt{n\sqrt{n\sqrt{n}}}...$. Then you have $x=\sqrt{n x}$ or $x^2=n x$ which gives you $x=n$ for any $n$, including $n=2$ – Dr. Wolfgang Hintze Sep 24 '18 at 07:50