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What does it mean for an odd function to be odd about an end of an interval (at $x=L$, when the interval is $[0,L]$ or $[-L,L]$)?

E.g. the sine function is odd under reflection about $0$, but also about the end $L$ of the interval $[0,L]$.

What does this mean? Does it mean that it doesn't matter at which interval (containing $0$) one watches the sine, it will still be odd.

mavavilj
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1 Answers1

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It means that $$f(L-x)=-f(L+x)$$

Empy2
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