Is there an example of a closed symplectic $6$-manifold and a closed lagrangian sub-manifold, which is diffeomorphic to a hyperbolic $3$-manifold?
Asked
Active
Viewed 103 times
5
-
Could you clarify what do you mean by "closed" ? I interpret it as "compact without boundaries" but a compact submanifold can't be hyperbolic. – Nicolas Hemelsoet Jul 24 '18 at 11:37
-
Yeah, I mean compact without boundary. Please could you explain why a compact sub-manifold cannot be hyperbolic? – Nick L Jul 24 '18 at 12:50
-
Sorry this is wrong, I was thinking to something else. – Nicolas Hemelsoet Jul 24 '18 at 13:31
-
You might wish to add a few tags to your question. The (symplectic-geometry) tag is not the most watched, and it is rather more symplectic geometry oriented than symplectic topology oriented, your question belonging to the latter field. Moreover my (probably exaggerated) impression is that 3-manifolds are not so well-known to many symplectic topologists. People in differential geometry/topology or in complex/kaehler geometry might be more capable of producing an example or a counter-argument, so I would advice that you try to reach them. – Jordan Payette Jul 28 '18 at 16:52