I need to prove that $$1-\frac12+\frac13-\cdots-\frac1{200} = \frac1{101}+\frac1{102}+\cdots+\frac1{200}$$ I have tried to relate it to various expansions of Taylor Maclaurin series but to no avail. Please do not solve the problem. I need a hint.
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5Hint: $-\frac12 = \frac12 - 1, -\frac14 = \frac14 - \frac12, \cdots, -\frac{1}{200} = \frac{1}{200} - \frac{1}{100}$ – achille hui Jul 04 '18 at 07:02
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Thanks Sir I got it – Akash Roy Jul 04 '18 at 07:03
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Also, see this comment by zyx. Comes to much the same thing but in a single strike. – Jyrki Lahtonen Jul 04 '18 at 07:42
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1@achillehui: I'd call that an answer :-) – joriki Jul 04 '18 at 07:54