How do you go from $$\sum_{0}^\infty (0.5e^-jw)^n$$
to
$$\frac{1}{1-0.5e^-jw}=\frac{e^jw}{e^jw-0.5}$$
and I was looking and this formula
$$\sum_{m=0}^{m=n} (a)^n = \frac{1-(a)^(n+1)}{1-a}$$
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Thank you. I know it's a geomatric series but I am stuck with algebra. Need someone to show the work. – R SMITH Jun 25 '18 at 19:28
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is the formula in the link the same as the one I am looking at? – R SMITH Jun 25 '18 at 19:42
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Thank you. I got it – R SMITH Jun 25 '18 at 19:43