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let $$A=\begin{pmatrix}1&2 &0\\0&0&-2\\0&0&1\end{pmatrix}.$$ and define for $x,y, z$ $\in R$

$Q(x,y,z) $= $(x,y,z) A \begin{pmatrix}x\\y\\z\end{pmatrix}$

which of the following satement is True ?

a) The matrix of second order partial derivatives of the quadratics form Q is $2A$

b) The ranks of the quadratics form $Q$ is $2$

c) The signature of the quadractic Form Q is$ (+,+,0)$

d) The Quadratics Form $Q$ takes the Value 0 for some non zero vectors $(x,y,z)$

My attempts : Matrix A has ranks 2 and it has 2 postive sigen, and one is 0,,,,in my thinking option 2 and and option 3 is correct...

is my answer is correct..??

Any hints/solution will be appreciated,,,,

i would be th thanksfuls..

jasmine
  • 14,457

1 Answers1

2

We have that $A$ can be divided as the sum of a symmetric and a skew part

$$A=B+C=\begin{pmatrix}1&2 &0\\0&0&-2\\0&0&1\end{pmatrix}=\begin{pmatrix}1&1 &0\\1&0&-1\\0&-1&1\end{pmatrix}+\begin{pmatrix}0&1 &0\\-1&0&-1\\0&1&0\end{pmatrix}$$

with $x^TCx=0$ and for the symmetric part $B$ we have

  • $\det(1)=1>0$
  • $\det\left(\begin{smallmatrix}1&1 \\1&0\end{smallmatrix}\right)=-1<0$
  • $\det(B)=-2<0$

therefore the signature for $B$ and thus for $A$ is $(+,+,-)$.

user
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