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When it says the side length of a cube was measured to be 20mm to the nearest millimeter. In this case, can I regard the maximum error for the side to be 0.5 mm? to compute the absolute error of the volume (if it was measured to be $8000mm^3$)? I am just confused with 'the nearest millimeter' how I should interpret this mathematically.

Thank you

user1917231
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1 Answers1

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Yes, the error of $\pm 0.5$mm would be assumed by "to the nearest millimeter". That means the unknown side length $a$ is bounded by $19.5$mm $ \le a \le 20.5$mm.

Ingix
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