Show that $\{\frac{e^n}{n!}\}$ converges.

Question

I know that the sequence $\{\frac{e^n}{n!}\}$ converges and that for prove it i have to limit it, but i don't know how do it.
In fact, i know that $\{\frac{x^n}{n!}\}$ converges, but i don't know prove it.
i want to aclarate that is convergence of the sequence, isn't of te serie.

Whether intentional or not, you have posted the same question twice in a short space of time. Please refrain from this: all new questions appear on the front page, and your original question is still very much there. — Rhys Hughes, May 22 '18 at 18:21

score 2 · Accepted Answer · answered May 22 '18 at 18:27

2

If $n>3,$ then

$$\frac{e^n}{n!} = \frac{e}{n}\cdot\left(\frac{e}{n-1}\cdot\cdots \cdot \frac{e}{3}\right )\cdot\frac{e}{2}\cdot\frac{e}{1} < \frac{e^3}{2n} \to 0.$$

answered May 22 '18 at 18:27

zhw.

105,693

Show that $\{\frac{e^n}{n!}\}$ converges.

1 Answers1