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What is the probability that $$ax^2 + bx + c = 0$$ has real solutions if $a, b, c$ are Poisson variables with common mean $\lambda$?

This seems to require evaluating $P(b^2 - 4ac \geq 0)$, which is the sum $$e^{-3\lambda} \sum_{\substack{a, b, c \geq 0 \\ b^2 \geq 4ac}} \frac{\lambda^{a + b + c}}{a!b!c!}.$$ I'm not even sure how to begin evaluating such a thing though.

The question is straightforward if only one of the three coefficients is random, but even two makes it difficult. I would happily accept an answer to the question when, say, only $b$ and $c$ are random.

Robert D-B
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  • What information do you need about this probability, beyond just a formula for it? Is there any reason to think that sum has any kind of closed form representation? – Jack M May 17 '18 at 18:01
  • My question was inspired by this similar question, where there was a very explicit answer. The Poisson is a "nice" discrete distribution, so it seemed natural to wonder if the same question had a similarly nice answer for it. – Robert D-B May 17 '18 at 18:25

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