I have a question about chain rule example.
The below equation is from Elementary Differential Equations and Boundary Value Problems by William E.Boyce
$\frac{dp/dt}{p-900} = \frac{1}{2} \dots (1)$
$\frac{d}{dt}\ln\lvert p-900 \rvert = \frac{1}{2} \dots (2)$ by the chain rule
I have no idea of how to derive (1) -> (2) by the chain rule.
Can you please show how to derive?