We seem to be able to define most other trigonometric functions, including the hyperbolic tangent function visually, in terms of a geometric projection.
Is it possible to define the hyperbolic cotangent in a similar geometric way?
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1Related: "Geometric construction of hyperbolic trigonometric functions". In particular, my answer may be helpful. – Blue May 01 '18 at 07:20
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Thanks, this helped! I was confused because I didn’t consider the tangent of the conjugate hyperbole. Upvoted but it’ll only be visible when I reach 15 rep. :) – Andrew Peter Prifer May 01 '18 at 07:25