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I have this question,

The number of different words that can be formed using all the letters of the word “MATHEMATICS” are?

I solved using the logic that if there are total 11 places so at all the 11 places all the 11 words can come, which gives me 11 to the power 11which is then divided by $2!*2!*2!$ due to the words M, T and A appearing 3 times.

But the actual solution is $11!/(2!*2!*2!)$, why did they consider “not repetition” ?

  • 2
    Is the usual interpretation of "using all the letters of the word". Example for SE: https://math.stackexchange.com/questions/483277/how-many-different-words-can-be-formed-using-all-the-letters-of-the-word-googolp. – Martín-Blas Pérez Pinilla Mar 21 '18 at 09:35
  • Even if the problem were asking with repetition (which it isn't), your answer would be wrong. Clearly $11^{11}/2^3$ is not an integer. If it were with repetition, the answer would be $8^{11}$ (assuming you mean strings with $11$ letters taken from the alphabet {M,A,T,H,E,I,C,S}).. – anon Mar 21 '18 at 09:39

1 Answers1

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Your power means repetition. $11^{11}$ is the cardinal of a cartesian product $X\times\cdots\times X$ (11 times). of a set $X$ with 11 elements.