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I've seen this in various questions like this one here: Prove that the inverse image of an open set is open

I know $(x,y)$ is an open interval, but when someone refers to an open set as $B(x,y)$, what exactly does that mean?

Eric Wofsey
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Jax
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It means an open ball centered at $x$ with radius $y$.

$$B(x,y) = \{ z: \|z-x\| < y \}$$

Siong Thye Goh
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