What is the proper definition of the distribution underneath this notation?
Since "$x\mapsto \delta(x)$" is define with respect to the distribution $\delta$ such that $$\langle \delta, f \rangle = f(0) $$ is "$(x,y)\mapsto \delta(x+y)$" define with respect to the distribution $T$ such that (with $g\in \mathcal{S}(\mathbb{R}^2)$) $$\langle T, g \rangle = \int_\mathbb{R} g(x,-x) d x \ ?$$
Attempt :
If I try to use "$(x,y)\mapsto \delta(x+y)$" to define my distribution as if it were a true function (and assuming Fubini is working for the sake of the guess), I would have $$\hspace{-50pt} \begin{align*} \langle T, g \rangle & =\iint g(x,y)\delta(x+y)dx dy \\ & = \int \bigg(\int g(x,y)\delta(x+y) dx\bigg) dy \\ & = \int g(-y,y) dy \tag{$= \int g(x,-x) dx$, with $x=-y$} \end{align*} $$ (since $\int g(x,y)\delta(x+y) dx=\langle \delta_{-y}, g(.,y) \rangle=g(-y,y)\ $).
Generalisation
If $h:\mathbb{R}^n\rightarrow \mathbb{R}$ the distribution $\delta_h$ denoted by $\delta(h(x))$ is define by $$ \langle \delta_h, g \rangle = \int_{\{h(y)=0\}} g(x) d x, \quad g\in \mathcal{S}(\mathbb{R}^n) $$