I am unable to solve the summation of cosine value from 0 to 89 degrees. Please help me. Thank you.
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Easier using complex numbers.
$$\sum_{k=0}^{89}e^{ik\pi/180}=\frac{e^{i\pi/2}-1}{e^{i\pi/180}-1}=\frac{(i-1)(e^{-i\pi/180}-1)}{|e^{i\pi/180}-1|^2}.$$
Then the real part is
$$\frac{1-\cos\frac{\pi}{180}+\sin\frac{\pi}{180}}{(\cos\frac\pi{180}-1)^2+\sin^2\frac\pi{180}}.$$
The sum of the sines comes as a byproduct.