Consider this conditional statement: If the safety net is broken, then I will fix it.
We have a rule in logic that says ( true implies false is false) . That is if the 1st part were true that the safety net was really broken , and the 2nd part were false that I'm not going to fix it, then the whole statement becomes false. This is clear till now.
We also have that: false implies true is true. That means that if the safety net was not broken, then I'm going to fix it , but that shouldn't turn the whole statement true , because if it weren't broken then certainly I am not going to fix it..
So.. any help?
any help?
With what? Once you proved "P(x) implies Q(x)" in general, its truth value will not change depending on "x". Since you posted to MSE, compare your example to "if $n \in \mathbb{Z}$ is even, then $n+2$ is even". That's as true for $n = 42$ as it is for $n=1001$. – dxiv Dec 24 '17 at 07:06If n is even ... then n+1 is even
That is a provably false statement, always.... then the whole statement becomes false not true
So you changed a statement that was always true to something entirely different, and the new statement happens to be false after your change. Sorry, don't know what you find to be surprising here. – dxiv Dec 24 '17 at 08:47