$f$ is continuous in $I$
Show that if $f$ satisfies the condition $f(\frac{x+y}{2})<\frac{1}{2}(f(x)+f(y))$ so it's convex
What I have to show here is $f(k_1y_1+k_2y_2+..k_ny_n)<k_1f(y_1)+k_2f(y_2)+...k_nf(y_n)$ such that $k_1+k_2+...+k_n=1$
The problem is I don't know how to find those coefficients $k$.