Prove that $A$ is a singular matrix if and only if zero is an eigenvalue (of $A$)

Asked Dec 07 '17 at 04:33

Active Dec 07 '17 at 04:41

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I am completely confused about this one. I know that a singular matrix is a matrix that does not have an inverse

I also know that I can find the eigenvalues of a matrix by finding the determinant of $A - yI$ so i guess i have to solve $A-0I$ which is just equal to $A$. But I dont think this tells me anything...

But that's about all i know, any help will be appreciated

edited Dec 07 '17 at 04:41

user1337

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asked Dec 07 '17 at 04:33

Soon_to_be_code_master

thank you, i didn't see that post. You can delete this post if you want – Soon_to_be_code_master Dec 07 '17 at 04:37
@Soon_to_be_code_master You should be able to delete it yourself. – Travis Willse Dec 07 '17 at 04:39

Prove that $A$ is a singular matrix if and only if zero is an eigenvalue (of $A$)

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