For any set $A$, prove that the cardinality of $A$ is no larger than the cardinality of $\mathcal{P}(A)$.
Please help! Thanks!
For any set $A$, prove that the cardinality of $A$ is no larger than the cardinality of $\mathcal{P}(A)$.
Please help! Thanks!
Hint: For each $a$ in $A$, the powerset $\mathcal{P}(A)$ contains the element $\{ a \}$.