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Show that a metric space $(X,d)$ is totally bounded(ball compact) if and only if every sequence in X has a Cauchy subsequence.

I already proved that if $(X,d)$ is ball compact, then every sequence in X has a Cauchy subsequence. But I have no idea how to the other part.

NYRAHHH
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  • See here: https://math.stackexchange.com/questions/556150/metric-space-is-totally-bounded-iff-every-sequence-has-cauchy-subsequence – Math1000 Oct 30 '17 at 05:20
  • Just out of curiosity, what does "ball compact" mean? – bof Oct 30 '17 at 08:13

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